Spheres in three-dimensional space (3D)
Similar to the circles in the plane there are spheres in three-dimensional space.
A vector representation is also possible for spheres.
$(\vec{x}-\vec{x_M})^2=r^2$
Like the circles, the cartesian equation of the sphere is derived from this.
$(x-x_M)^2+(y-y_M)^2$ $+(z-z_M)^2=r^2$
- $r$ is the radius
- $M(x_M|y_M|z_M)$ is the center
i
Hint
Spheres in 3D have many similarities to the circles in the plane (2D). Since we are in space, there is also a z coordinate for the spheres.
Point on sphere: position of point and sphere
We also insert the point $P(x_0|y_0|z_0)$ in the front part of the sphere equation.
$(x_0-x_M)^2+(y_0-y_M)^2$ $+(z-z_M)^2$
Now we distinguish 3 cases again. The result is
- $=r^2$: The point is on the sphere.
- $<r^2$: The point is inside the sphere.
- $>r^2$: The point is outside the sphere.