Parallel lines
Parallel lines are divided into parallel and coincident lines.
For determining if lines in three-dimensional space are parallel or coincident the processing scheme can be used.
Coincident lines
Coincident lines are one and the same line with only a different equation.
Requirements
- The direction vectors are collinear
- The position vector of one line has its terminal point on the other line (Finding out if a point is on a line)
Parallel lines
Lines with parallel direction vectors which are not coincident are parallel.
Requirements
- Direction vectors are collinear
- The terminal point of the position vector of one line is not on the other line
Info
Example
$\text{g: } \vec{x} = \begin{pmatrix} 3 \\ 4 \\ 6 \end{pmatrix} + r \cdot \begin{pmatrix} -3 \\ 5 \\ 2 \end{pmatrix}$
$\text{h: } \vec{x} = \begin{pmatrix} -3 \\ 14 \\ 10 \end{pmatrix} + s \cdot \begin{pmatrix} -3 \\ 5 \\ 2 \end{pmatrix}$
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Are the direction vectors collinear?
First, examine if the direction vectors are multiples of each other (=collinear).$\vec{a}=t\cdot\vec{b}$
$\begin{pmatrix} -3 \\ 5 \\ 2 \end{pmatrix}=t\cdot\begin{pmatrix} -3 \\ 5 \\ 2 \end{pmatrix}$
Calculate $t$ for every row
$-3=t\cdot(-3)$
$5=t\cdot5$
$2=t\cdot2$If $t$ equals the same in each row (here: $t=1$) then the vectors are collinear.
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Insert the vector of $h$ into $g$
Now the position vector of one line (here: $h$) is inserted into the other.$\begin{pmatrix} -3 \\ 14 \\ 10 \end{pmatrix} = \begin{pmatrix} 3 \\ 4 \\ 6 \end{pmatrix} + r \cdot \begin{pmatrix} -3 \\ 5 \\ 2 \end{pmatrix}$
Now we set up the equation system and solve it. If $r$ equals the same in every equation, then the terminal point of the position vector is on both lines and thus they are coincident.
- $-3=3-3r$
- $14=4+5r$
- $10=6+2r$
- $r=2$
- $r=2$
- $r=2$
=> The lines are coincident.