Point on the line?
This is to check whether a point lies on a given line.
i
Method
- Insert the position vector of the point for $\vec{x}$ into the linear equation
- Set up equation system (one equation per row)
- Check if $r$ is the same for each row
Example
Is the point $A(-3|14|10)$ located on the line $g$?.
$\text{g: } \vec{x} = \begin{pmatrix} 3 \\ 4 \\ 6 \end{pmatrix} + r \cdot \begin{pmatrix} -3 \\ 5 \\ 2 \end{pmatrix}$
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Insert $A$ in $g$
The position vector (vector with coordinates of the point) of $A$ is used for $\vec{x}$ in $g$.$\begin{pmatrix} -3 \\ 14 \\ 10 \end{pmatrix} = \begin{pmatrix} 3 \\ 4 \\ 6 \end{pmatrix} + r \cdot \begin{pmatrix} -3 \\ 5 \\ 2 \end{pmatrix}$
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Set up equation system
Now we set up the equation system and solve it. Every row is an equation.- $-3=3-3r$
- $14=4+5r$
- $10=6+2r$
- $r=2$
- $r=2$
- $r=2$
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Check
If there is no contradiction and $r$ is equal in all equations, then the point is on the line.I, II, III: $r=2$
=> Point $A$ is located on the line.